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the base of a solid is the region in the first quadrant bounded by the line x+2y=4 and the coordinate axes. what is the volume of the solid if every cross section perpendicular to the x-axis is a semicercle
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when x=0 : y = 2 when y = 0: x= 4 Correct answer is 2pi/3
radius = 2 i believe they mean forming a sphere, if you can imagine a 2d circle with a radius of 2 being "circled" about (for lack of a better word) around a 3d axis to create a sphere. the volume of a sphere is 4/3pi*r^3, which would make the volume of this sphere (32/3)pi
Volume = (1/2) *1/3 (3.14) (R)^2 (H) V = (1/2) 1/3 (3.14)(1)^2 (4) V = 4pi/6 2 pi/3
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