Question

Solve the given equation.

cos θ = sqrt3/2

Answer 1

I got \[\theta =\pi/6+2kpi,\theta= 2\pi/6 +2kpi\]

Answer 2

principle value is pi/6

Answer 3

yes

Answer 4

general value is\[2k \pi \pm \pi/6\]

Answer 5

so i was right?

Answer 6

Well maybe for the second part.

Answer 7

to some extent.....
you wrote just + it could be a '-' too....
and i didn't get how did that pi/6 became 2pi/6

Answer 8

Wouldn't I just add 2pi/6 to pi/6 to get 2pi/6??