Question

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Answer 1

domain is all real values

range:
y+1 = 2(3^x)
(y+1)/2 = 3^x

log_3 (y+1)/2 = x

so all real values for this one too...

y intercept is 1

Answer 2

Domain is all real,
Range
\[{y \in \mathbb{R}:y>-1}\]

Answer 3

@kk1022 you're correct

Answer 4

yes

Answer 5

y-intercept at 1
no x intercept

Answer 6

actually there is x intercept, but its decimal i think

Answer 7

just substitute y=0
0 = 2(3^x) − 1
1/2=3^x
ln(1/2)=xln3
x=(ln3)/ln(1/2)