What's the spring constant based on the given quantities?
http://i42.tinypic.com/1z68ioi.png shows the quantities.

A) mv^2/A^2
B) Mv^2/A^2
C) m^2v^2/(m+M)A^2
D) (M+m)^2v^2/mA^2

Thank you!

Question

What's the spring constant based on the given quantities?
http://i42.tinypic.com/1z68ioi.png shows the quantities.

A) mv^2/A^2
B) Mv^2/A^2
C) m^2v^2/(m+M)A^2
D) (M+m)^2v^2/mA^2

Thank you!

mani_jha · Answer

The initial energy  of the system is: mv^2/2
The final energy is: 0+kA^2/2
Equate and get your answer.

anonymous · Answer

kinetic energy of bullet is converted to ==== potential energy of spring (by displacing it)