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Physics 26 Online
OpenStudy (anonymous):

What's the spring constant based on the given quantities? http://i42.tinypic.com/1z68ioi.png shows the quantities. A) mv^2/A^2 B) Mv^2/A^2 C) m^2v^2/(m+M)A^2 D) (M+m)^2v^2/mA^2 Thank you!

OpenStudy (mani_jha):

The initial energy of the system is: mv^2/2 The final energy is: 0+kA^2/2 Equate and get your answer.

OpenStudy (anonymous):

kinetic energy of bullet is converted to ==== potential energy of spring (by displacing it)

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