Question

If x varies inversely as y and directly as t, and x = 12 when t = 10 and y = 25, find y when x is 6 and t = 3.

Answer 1

x =kt/y

12 = 10k/25
275 =10k
k = 27.5

6 = 3(27.5)/y

y = 3(27.5)/6
y = 13.75

Answer 2

\[\ \huge {x1 \over x2} = {y2 \over y1}\]
\[\huge {x1 \over x2} = {t1 \over t2}\]

Answer 3

let x1=12 , t1=10 , y1 = 25