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OpenStudy (anonymous):
Factor completely: 5ab + 3ay + 5b + 3y
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OpenStudy (anonymous):
a( 5b + 3y) _ 5b +4y = (5b + 3y) (a-1)
OpenStudy (anonymous):
5b (a +1)+ 3y (a+1)= (a+1)(5b+3y) another approach
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