Question

The radioactive isotope plutonium-239 has a half-life of 24110 years.

The decay constant of plutonium-239 is??

Answer 1

half of 24110 is 12055

Answer 2

so 239* (1/2)^12055?

Answer 3

= what?

Answer 4

woops i mean -239*(1/2)^12055=

Answer 5

No thats incorrect
http://en.wikipedia.org/wiki/Exponential_decay

Answer 6

lamda is a decay constant, it is equal to ln2/half life

Answer 7

sorry for wrong information ...

decay constant = ln2/(half life)

Answer 8

oh ok so -239*(ln2/12055)

Answer 9

no ... just (ln2/24110)
and also change 24110 to seconds.

ie (ln2/24110*364.25*24*60*60)

Answer 10

239 is name of isotope of plutonium

Answer 11

just 239? or negative

Answer 12

this is you answer (ln2/(24110*364.25*24*60*60))

Answer 13

i dont need to solve?

Answer 14

http://en.wikipedia.org/wiki/Exponential_decay#Half-life

and also look for decay constant here ... you dont need to solve

Answer 15

thanx