Question

Factor the trinomial, if possible.
8a^2+11ab-10b^2

Answer 1

ac=8*-10=-80
you want 2 factors of -80 that add up to 11, both have different signs
16 and -5
8a^2-16ab+5ab-10b^2=
8a(a-2b)+5b(a-2b)=
(a-2b)(8a+5b)

Answer 2

I now see though, that you missplaced the signs for the 16ab and the
-5ab in your equation. It should be (a+2b)(8a-5b). Thanks for walking me through the process.

Answer 3

ah you're right, i did misplace the signs lol