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Determine the sum or difference in clock 12 arithmetic. (6 + 1) + 12 A. 19 B. 8 C. 7 D. 3
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clock 12 arithmatic?
??
C, 7! :]
thanks
6+1=7 7+12= 15 15-12=3
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6 + 1 is 7. 12 hours later than 7 is 7. I must be doing this wrong, how could it be 3?
7+12=15 15-12=3
(6+1) + 12 7 + 12 19 .... oops, made a mistake here.... 7 So (6+1) + 12 = 7 (mod 12)
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