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Mathematics 17 Online
OpenStudy (anonymous):

(cos2x)(sinx)=1

OpenStudy (anonymous):

use the double angle formula for cos2x and get the equation in terms of only sin. you'll have a trig equation in quadraic form.

OpenStudy (anonymous):

(1-2sin^2x)(sinx)=1

OpenStudy (anonymous):

wow, two problems at once eh? ok, now multiply it out.

OpenStudy (anonymous):

(sinx)-(sin^3x)=1 (sin^3x)-sinx+1

OpenStudy (anonymous):

hmm. looks like it's not quadratic. btw. you should have : sinx - 2sin^3x = 1

OpenStudy (anonymous):

so we have 2sin^3x - sinx + 1 = 0

OpenStudy (anonymous):

yes i just fogot the 2.

OpenStudy (anonymous):

|dw:1332976122921:dw| can you factor this?

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