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Mathematics 17 Online
OpenStudy (anonymous):

y^2+2y+5-3y^2-5y

jimthompson5910 (jim_thompson5910):

y^2+2y+5-3y^2-5y (y^2-3y^2)+(2y-5y)+5 -2y^2-3y+5 So y^2+2y+5-3y^2-5y = -2y^2-3y+5 for all values of 'y'

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