he cartesian equation of the circle C is
x^2 + y^2 -8x - 6y +16 = 0

a) Find the coordinates of the centre of C and the radius of C.

i got (x-4)^2 + (y-3)^2 = 3^2
centre of C (4,3) radius = 3

b) Sketch C.

i did this as well

c) Find in parametric equations for C (im stuck on)

d) Find, in cartesian form, an equation for each tangent to C which passes through the origin O. (Im stuck on)

Question

he cartesian equation of the circle C is
x^2 + y^2 -8x - 6y +16 = 0

a) Find the coordinates of the centre of C and the radius of C.

i got (x-4)^2 + (y-3)^2 = 3^2
centre of C (4,3) radius = 3

b) Sketch C.

i did this as well

c) Find in parametric equations for C (im stuck on)

d) Find, in cartesian form, an equation for each tangent to C which passes through the origin O. (Im stuck on)

amistre64 · Answer

|dw:1332979200028:dw|

amistre64 · Answer

well, if its 3 up from the x axis and its radius is 3; then one of its tangents IS the x axis

amistre64 · Answer

|dw:1332979359399:dw|

amistre64 · Answer

|dw:1332979403205:dw|

3+5 = 8 up
and 4 is just 4 over so our slope is 8/4 = 2

y = 2x is the other tangent line