Consider the curve given by x^2+3y^2= 1 +3xy
show that dy/dx = 3y-2x / 6y-3x

ok so while i was doing this by hand I ended up with 3y-2x / 6y. I dont know what happened but that 3x on the bottom threw me off. O.o help?

Question

Consider the curve given by x^2+3y^2= 1 +3xy
show that dy/dx = 3y-2x / 6y-3x

ok so while i was doing this by hand I ended up with 3y-2x / 6y. I dont know what happened but that 3x on the bottom threw me off. O.o help?

liizzyliizz · Answer

HELP :(

accessdenied · Answer

do you have your work to get there?

anonymous · Answer

@liizzyliizz Show us your work, so we know where you misunderstood!

liizzyliizz · Answer

okey dokes I shall do that now.

liizzyliizz · Answer

|dw:1332986182859:dw| ok so i was looking at my work, and i have both of these things written down. I know somewhere I went wrong, and started doing something that doesn't make much sense, but I haven't been able to figure out what I am forgetting to do.