Question

Explain, in complete sentences, how to factor 4x2 – 4x – 48. Explain how your factors could be checked for accuracy

Answer 1

let f(x)= 4x^2 – 4x – 48=4(x^2-x-12)
f(4)=0
therefore, x-4 is a factor of f(x)
f(-3)=0
therefore, x+3 is a factor of f(x)
deg(f(x))=2 therefore, it has two roots
therefore, f(x) =4(x-4)(x+3)

Answer 2

Extract the common factor 4 getting
4(x2-x-12)
then factor the remainder getting: (x-4)(x+3) put them together and get
4(x-4)(x+3)

Answer 3

To check for accuracy simply multiply your results to determine if you end up with the original expression

Answer 4

The first step to factorization is to take out a highest common factor, which in your case is 4 .
4(x^2-x-12)
Now you have to ask yourself what multiplys to give -12 and and adds to give -1, well its right, -4,3
4(x-4)(x+3)
to check you can expand again and you should end up with a original question

Answer 5

Thank you ,this helps
alot