Question

w varies jointly as x and y and inversely as the square of z. If w = 280 when x = 30, y = 12, and

z = 3, find w when x = 20, y = 10 and z = 2.

Answer 1

so w=kxy/(z^2)
now in order to find w when x=20, y=10 and z=2, we must first find k or the proportionality constant...
let's do that using the other information where w=280 if x=30, y=12 and z=3
manipulating this equation we'll have
k=w(z^2)/xy
k=280(3^2)/30*12
k=280*9/360
k=7
now that we know k, we can now compute for w when x = 20, y = 10 and z = 2:

w=kxy/z^2
w=7*20*10/2^2
w=1400/4
w=350 <----the answer

Answer 2

this is called a combined variation. Or simply a combination of the other kinds of variation or relationship

Answer 3

^idk you but I think I love you.

Answer 4

@rebeccaskell94 lol :))