How would i find the square root of 3.344x10^-27? How about 8.36x10^-28?

By that I mean if i had the following problem:
1.881x10^-11=8.36x10^-28 x v1f^2 + 3.344x10^-27 x v2f^2
and v1f=150000000 - 4v2f
I would get
1.881x10^-11=8.36x10^-28 (15x10^7 - 4v2f) + 3.344x10^-27 x v2f^2

Therefore how would I write down the square root of both sides?

Question

How would i find the square root of 3.344x10^-27? How about 8.36x10^-28?

By that I mean if i had the following problem:
1.881x10^-11=8.36x10^-28 x v1f^2 + 3.344x10^-27 x v2f^2
and v1f=150000000 - 4v2f
I would get 
1.881x10^-11=8.36x10^-28 (15x10^7 - 4v2f) + 3.344x10^-27 x v2f^2

Therefore how would I write down the square root of both sides?

anonymous · Answer

By the way v1f and v2f are the final velocities. It's a physics question but i've forgotten how to do it somehow

anonymous · Answer

$$1.881\times 10^{-11}=8.36\times 10^{-28} \times  v1f^2 + 3.344\times 10^{-27} \times v2f^2$$ is the is the problem?  what is the variable?

anonymous · Answer

$$1.881\times 10^{-11}=8.36\times 10^{-28} \times  ( 150000000 - 4v2f)^2+ 3.344\times 10^{-27} \times v2f^2$$

anonymous · Answer

Nevermind I got it now. All i wanted to know was how to find something like $$\sqrt(8.36×10−28×v1f2$$ and because i was tired i forgot how to do it. thanks for replying