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Solve for x. log6(2x + 3) = 3
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\[6^3=2x+3\]
log6(2x + 3) = 3 6(2x + 3) = 10^3 2x+3 = 1000/6 x= 491/6
\[\log_b(x)=y\iff b^y=x\] you need to know who to switch back and forth easily , or rather you need to be able to switch easily for your math class
6^3 = 2x + 3 by definition of logs 216 = 2x + 3 213 = 2x 106.5 = x
you get to mertsj answer in one step by rewriting in exponential form
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Listen to Satellite. He is the wise one.
I have just found that 6 is the base. Sorry for that!
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