Question

c+(4-3c)-2=0 help me solve this plez

Answer 1

\[c + (4-3c)-2 = 0\]
parenthesis unnecessary:
\[c + 4 - 3c - 2 = 0\]
combine like terms:
\[-2c + 2 = 0\]
isolate c:
\[-2c = -2\]
divide by -2:
\[c = 1\]

Answer 2

how u get the -2c+2=0