Question

What are the x– and y–intercepts of y = 2x2 – 10x + 8? Can someone show me how to get the answer?

Answer 1

x int. = 3
y int. = 8

Answer 2

To find intercept with the y-axis you set x to 0 (because the y-axis is located where x=0) and solve for y.
y = 2(0)^2 - 10(0) + 8 = 8, so intercept is at (0,8)

To find intercept with the x-axis you set y to 0 (because the x-axis is located where y=0) and solve for x.
2x^2 - 10x + 8 = 0
(2x - 2)(x - 4) = 0
2x -2 = 0 or x - 4 = 0 so intercepts at (1,0) and (4,0)