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OpenStudy (anonymous):
x2-6x+5=0 solution to the equation thanks
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OpenStudy (anonymous):
(x-5)(x-1) = 0, x = 5, 1
OpenStudy (anonymous):
can i see it step by step please
OpenStudy (anonymous):
x^2 - 6x + 5 = 0 so factorise this using two numbers which add to give -6 and multiply to give +5 (x-5)(x-1) = 0
OpenStudy (anonymous):
okidoki thnaks duck
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