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OpenStudy (anonymous):
Lithium bromide reacts with chlorine gas to form lithium chloride and bromine. How many moles of lithium chloride will be produced from 0.046 mol of lithium bromide? 2LiBr+Cl2 > 2LiCl+Br2
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OpenStudy (anonymous):
\[.046mol LiBr \times \left( 2 mol LiCl \div 2mol LiBr \right)=0.046 mol LiCl\]
OpenStudy (anonymous):
simple substitution derived from the balanced chem forumula save the issue of doing math.
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