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Find the third term in the binomial series from (a+b)^11
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55(a^9)(b^2)
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\[\dbinom{11}{2}a^9b^2\]
\[\dbinom{11}{2}=\frac{11\times 10}{2}=11\times 5=55\]
Recall that this follows from\[(a+b)^n=\sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^{k}.\]
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