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Write y = 2/3 x + 3 in standard form using integers.
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first multiply by 3 3y = 2x +9 2x-3y +9 =0
is that answer because theres 4 choices A.–2x + 3y = 9 B.–2x + 3y = 3 C.3x – 2y = 9 D.–2x – 3y = 9
2x-3y +9 =0 2x-3y = -9 multiply by -1 –2x + 3y = 9 so A
thank you
my pleasure XD
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