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Mathematics 6 Online
OpenStudy (unklerhaukus):

Spot the error(s)

OpenStudy (unklerhaukus):

OpenStudy (unklerhaukus):

also i dont know how to do the steps between the question marks or the remaining step

OpenStudy (mertsj):

\[3a^2+ba+3a^2-b^2-3ab=6a^2-2ab-b^2 NOT 6a^2-ab-b^2\]

OpenStudy (unklerhaukus):

you are quite right @mertsj

OpenStudy (unklerhaukus):

i sure there are more though

OpenStudy (mertsj):

And the factors are (2a+b)(3a-b)

OpenStudy (mertsj):

So it must be that 3a-b=b in order to reduce to (2a+b)/4

OpenStudy (unklerhaukus):

are you sure about those factors?

OpenStudy (mertsj):

No. They are wrong.

OpenStudy (unklerhaukus):

\[(2a+b)(3a-b)=6a^2-2ab+3ab-b^2=6a^2+ab-b^2\]

OpenStudy (mertsj):

It won't factor.

OpenStudy (unklerhaukus):

that is one of the reason i believe i have made errors

OpenStudy (unklerhaukus):

or should i try completing the square

OpenStudy (unklerhaukus):

actually that wont work because of the 6

OpenStudy (unklerhaukus):

alternatively can you explain the method employed in the back of the book, specifically how to get form the second to the third line

OpenStudy (mertsj):

Well where are all the smart people.

OpenStudy (unklerhaukus):

i'll repost with that correction

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

That is a a solid piece of work cinar thank you very much,

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