Mathematics
6 Online
OpenStudy (unklerhaukus):
Spot the error(s)
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OpenStudy (unklerhaukus):
OpenStudy (unklerhaukus):
also i dont know how to do the steps between the question marks
or the remaining step
OpenStudy (mertsj):
\[3a^2+ba+3a^2-b^2-3ab=6a^2-2ab-b^2 NOT 6a^2-ab-b^2\]
OpenStudy (unklerhaukus):
you are quite right @mertsj
OpenStudy (unklerhaukus):
i sure there are more though
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OpenStudy (mertsj):
And the factors are (2a+b)(3a-b)
OpenStudy (mertsj):
So it must be that 3a-b=b in order to reduce to (2a+b)/4
OpenStudy (unklerhaukus):
are you sure about those factors?
OpenStudy (mertsj):
No. They are wrong.
OpenStudy (unklerhaukus):
\[(2a+b)(3a-b)=6a^2-2ab+3ab-b^2=6a^2+ab-b^2\]
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OpenStudy (mertsj):
It won't factor.
OpenStudy (unklerhaukus):
that is one of the reason i believe i have made errors
OpenStudy (unklerhaukus):
or should i try completing the square
OpenStudy (unklerhaukus):
actually that wont work because of the 6
OpenStudy (unklerhaukus):
alternatively can you explain the method employed in the back of the book, specifically how to get form the second to the third line
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OpenStudy (mertsj):
Well where are all the smart people.
OpenStudy (unklerhaukus):
i'll repost with that correction
OpenStudy (anonymous):
OpenStudy (unklerhaukus):
That is a a solid piece of work cinar
thank you very much,