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Solve equation using the quadratic formula. x^2+25=0. Please show me the steps.
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is this dealing with imaginary numbers?
we havn't done with imaginary numbers
ok
x^2+25 (x+5)(x-5)=0 x=-5, x=5
Is it difference between the squares
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Do u think we need not to use the quadratic formula
Add 25 to both sides of the equation to get x^2 = 25 Take the square root of both sides of the equation to get x = ±√25 = ±5 x = 5 and x = -5 are solutions to this equation. You can recognize that the difference of two squares is a standard form that you know the factors for. A2 - b2 = (a+b)(a-b) x2 - 25 = (x+5)(x-5) = 0 Values of x that make the factors zero are x = -5, x = 5 (same as above)
Does this help?
Yes .Thank you so much.
Anytime :-)
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