Question

Find the probability. An IRS auditor randomly selects 3 tax returns (without replacement) from 47 returns of which 5 contain errors. What is the probability that she selects none of those containing errors?

A. 0.0012

B. 0.0006

C. 0.708

D. 0.7136

Answer 1

i was thinking the hypergeometric probability

Answer 2

\[P(x)=\frac{\binom{N-M}{n-k}\binom{M}{k}}{\binom{N}{n}}\]
i think is how its set up

Answer 3

N items
M successes
n drawn
k of them are success

Answer 4

n= 3
N=47
M=47-5

What is the probability that she selects none of those containing errors (3) successes

is how im interping it

Answer 5

(5 choose 0)(42*41*40/3!)\(47*46*45/3!); thnx to wolfram = .7079 if its right :)