Question

One integer is 9 more than another. Their product is 162. Find integers.

PLEASE HELP...

Answer 1

x = y+9
x*y=162
(y+9)y = 162
y^2+9y=162
(y+4.5)^2-20.25=162
(y+4,5) ^2=182.25
y+4,5=sqrt182.25=13.5
y=9
and x equals 18

Answer 2

let the 1st number be x the 2nd number is x + 9

the product

\[x(x +9) = 162\]

solve

\[x^2 + 9x - 162= 0\]

factorising

(x + 18)(x - 9) = 0

x = -18 and 9

Answer 3

ah, yes, true, forgot the second answer