Question

find axis of symmetry and vertex
y=3x^2-12x+1
y=-2x^2+7x-21

Answer 1

y=3x^2-12x+1
y=3(x^2-4x)+1
y=3(x-2)^2-4(3)+1
y=3(x-2)^2-11
Vertex at (2,-11)
Symmetry at x=2

Answer 2

y=-2x^2+7x-21
y=-2(x^2-7x/2)-21
y=-2(x-7/4)^2-49/16 (-2)-21
y=-2(x-7/4)^2-119/8
Vertex at (7/4,-119/8)
Symmetry at x=7/4

Answer 3

hank you