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parametrize the curve y=ln(2x+1) using its slope m as the parameter ..
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help me please
slope of curve is its derivative, y' so: y' =2/(2x+1) ------>2x+1 = 2/y' puting this in the equation: y=Ln(2/y') you have your result
answer: x=(2-m)/2m y=ln[2/m)
just name y' = m
just keep in mind that m(x)
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hm ok thanks myko
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