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solve for x? 6^-x-2=13^-8x
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take log on both sides,
$6^{-x-2}=13^{-8x}$ ?
yes
\[6^{-x-2}=13^{-8x}\]
right
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\[\log_{10}{6^{-x-2}}= \log_{10}{13^{-8x\ [\rightarrow x = (-2\log_{10}{6} )/(\log_{10}{6}-8\log_{10}{} )\]}}\]
\[6^{-x-2}=13^{-8x}\implies (x+2)\ln(6)=8xln(13)\implies 8x \ln(13)-x \ln(6)=2 \ln(6)\]\[=x(8 \ln(13)- \ln(6))=2 \ln(6)\implies x=\frac{2 \ln(6)}{8 \ln(13)- \ln(6)}\]
the same log 10 or log e
Pretty cool, no?
ok, cool
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Yours was perfectly correct, but I thought maybe somebody would benefit from a little more detail.
yea, i expalin no detail
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