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Mathematics 14 Online
OpenStudy (anonymous):

The circle given by x^2+y-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21 What is the value of k in this equation?

OpenStudy (anonymous):

is that supposed to be a y^2 right after x^2 ?

OpenStudy (anonymous):

hello?

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