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Let θ be an angle in quadrant III such csc(θ)=-(13)/(5) Find the exact values of tan θ and cosθ ?
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Draw a picture. If you're using trig functions it's a right triangle, and the only right triangle that works with 5 and 13 is [5, 12, 13] (keep in mind what csc is, it tells us that 13 is the hyp). Knowing this, I'm sure you can figure out everything else after drawing a picture.
it's complicated!
cscθ=-(13)/(5) cscθ = 1/sinθ => sinθ = 1/cscθ = 1/(-13/5) = -5/13 |dw:1333174049433:dw| So can you find tan θ and cos θ yourself? remeber for quad. III, tanθ is positive and cosθ is negative!
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