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Mathematics 18 Online
OpenStudy (anonymous):

I need help with this: http://i1064.photobucket.com/albums/u368/Kreshnik-joker/Graph.jpg

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

2

OpenStudy (anonymous):

I don't need the answer... I need to know how to do it!

OpenStudy (anonymous):

(m+3)x+(2-3m)y-5=0 -> (m=3)1 +(2- 3m)0 -5=0 -> m+3-5=0 -> m=2

OpenStudy (anonymous):

^^ is correct

OpenStudy (anonymous):

Thank you... :D

OpenStudy (anonymous):

Only a substitute values ​​(representing the x) and 0 (representing y) in equation and isolating m. :)

Directrix (directrix):

(m +3)x + (2 - 3m)y - 5 = 0 --> with line passing through (1,0) x = 1 and y = 0, Substitute (m +3)*1 + (2-3m)*0 -5 = 0 (m+3) + 0 - 5 = 0 m + 3 +0 - 5 = 0 m - 2 = 0 m = 2

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