Question

Choose the slope-intercept equation of the line that passes through the point (6, 2) and is perpendicular to y = 3x + 6.

y = one thirdx

y = -one thirdx + 4

y = 3x + 20

y = -3x - 16

Answer 1

help!

Answer 2

did you get slope of line ?

Answer 3

Since the line is perpendicular to y = 3x + 6
slope of line y = 3x + 6 is 3 (Luis_Rivera has written that for you)
therefore slope of line x 3 = -1
slope of line = -1/3
Equation is
(y-y1) = m (x-x1)
Pur (x1, y1) = (6,2) and m = -1/3 into the equation
y - 2 = (-1/3) (x -6)
y = (-x/3) + 2 +2
y = -x/3 +4
So choose the suitable answer!!

Answer 4

m=-1/3
y-y1=m(x-x1)
y-2=-1/3(x-6)
y-2=-1/3x+2
y=-1/3x+4