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how does -(2x+y)/(x-2y) = (2x+y)/(2y-x)
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what do you have to find ?
-(a-b) is same as -a+b which is same as (b-a)
hahahaahah... NOW I GET IT ! \[\LARGE -\frac{2+xy}{x-2y}\;\;\; \text{can be written as...} \frac{2+xy}{-(x-2y)}\] and now you have SUROJ answer!
-(2x+y)(2y-x)=(2x+y)(x-2y) \[-(4xy+2y ^{2}-xy-2x ^{2})=2x ^{2}-4xy+xy-2y ^{2}\] 0=0 :D:D:D:D:D
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