1. For ABC, what is the value of cosC? 1. For ABC, what is the value of cosC?
\[CosC= \frac{adjacent \ side}{hypotenuse}\]
The choices are 0.5, 0.6, 0.8, and 0.9
We aren't going to tell you the answer, only how to solve the question.
I don't know how to solve the problem though.
0.8 100% ;)
thanks alirezamemarian!
alirezamemarian you should read the Code of Conduct :)
The way I see it the figure is drawn to scale...then Diyadiya's answer should help you further.
Nice job giving him the answer, but are you going to do that for the rest of his life?
That's why we teach people how to do things instead of give them the answer.
to all! ok yes! sorry! it`s better that we show the way of solve,not give them the answer,yes? :)
yes :)
I agree that someone should of showed me how, but No One did.
We were trying to show you ,But someone just gave you the final answer and you were happy with it If you want to know how i can help you :)
and @ inkyvoyd - I am a girl. :)
I would love to know how.
I didn't want @ali to think I didn't appreciate their help.
ok \[CosC= \frac{adjacent \ side}{hypotenuse} \] Do you know which is adjacent side and hypotenuse ?
yes I do.
So what do you get now ?
what do you mean?
\[CosC= \frac{adjacent \ side}{hypotenuse}\] To find Cos we divide adjacent side by Hypotenuse Which is adjacent side and hypotenuse in the figure ?
The hypotenuse is the AC line and the adjacent sides are the other sides AB and BC
Okay Hypotenuse is AC and value of AC is also given in the fig which is 90 Here since we are finding Cos C , adjacent side is the side adjacent to angle C ,Which is BC and value of BC is 72
okay
Now can you find CosC ? just divide adjacent side by hypotenuse
thats is \[\frac{BC}{AC}\]
so it would be 0.8? 72/90
Yes ! Right :)
thanks. i didn't know it was that simple. I couldn't find out how to do it in my book. Thanks for showing me how to do it.
Glad to help :) and you can keep this in mind while doing these kind of problem Sine is Opposite over Hypotenuse Cosine is Adjacent over Hypotenuse Tangent is Opposite over Adjacent
okay thanks for the help!! ;)
Anytime :)
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