Question

Use Lagrange’s method to find the maximum and minimum values of f(x,y)=y^2-x^2 on the ellipse: (((x^2)/4)+(y^2)=1)

Answer 1

Solution for the variable y= y=-1/2sq root 4-x^2
y= sqroot 4-x^2/2

Answer 2

The alternate forms are x^2+4y^2=4
x^2+y^2-1=0
1/4(x^2+4y^2)=1