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Simplify (3b2 – 2b + 3) – (5b2 + 4b – 2)
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8b2 – 6b + 5 8b2 – 2b + 5 –2b2 – 6b + 5 –2b2 – 2b + 5
(3b^2 – 2b + 3) – (5b^2 + 4b – 2) 3b^2 – 2b + 3 – 5b^2 - 4b + 2 (3b^2– 5b^2)+(-2b-4b)+(3 + 2) -2b^2-6b+5 So the answer is -2b^2-6b+5
Okaye thanks
I have forgotten how to add :'(
What is the slope of the line which passes through (2, 6) and (0, 2)?
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m = (y2-y1)/(x2-x1) m = ( 2- 6)/(0-2) m = (-4)/(-2) m = 2 So the slope of the line that passes through the two points is 2
2 –3 4 –2
What is the degree of the polynomial 3h2 – 4h + 1?
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