Question

Roots of the quadratic equation \( (a+b-2c)x^2-(2a-b+c)x + (a-2b+c) =0 \) are :

Answer 1

what have you tried?

Answer 2

i tried to to -b/a and c/a :S

Answer 3

so what am i supposed to do?

Answer 4

You have a+b and ab can't you find a and b ?

Answer 5

how?

Answer 6

Find a-b and then eliminate.

Answer 7

where did a-b come from?

Answer 8

It's a tedious process, I got a fairly critical form of r\mots:

\[ \frac{1}{2} \left(\frac{(2 a-b+c)^2}{(a+b-2 c)^2}\pm \sqrt{\frac{9 b^2-22 b c+c (8 a+9 c)}{(a+b-2 c)^2}}\right) \]

Answer 9

Oh ok thanks !

Answer 10

Actually the answer was none of the options