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OpenStudy (anonymous):
given 3e^(1-x^2) times ln(x) find the equation of the tangent line at x=1
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OpenStudy (anonymous):
Hint : You must take the derivative of the equation. Be careful when doing so because you must use the chain and product rule. From there, you plug in your x = 1 and calculate the slope. Then plug the numbers into point-slope form of a line: y2-y1 = m * (x2-x1) and you are done.
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