Question

(8r - 3) - (7r + 1) = -6 Solve and check your solution. So far I have (8r - 7r) - (-3 + 1) = -6
r - 2 = -6 r = -4 Check (8[-4] - 3) - (7[-4] + 1) = -6 (-32 - 3) - (-28 + 1) = -6 -35 - (-27) does not = -6 HELP!!!!!

Answer 1

(8r - 3) - (7r + 1) = -6
8r - 3 - 7r - 1 = -6
8r - 7r - 3 - 1 = -6
r - 4 = -6
r = -6 + 4
r = - 2

Answer 2

Check:
(8r - 3) - (7r + 1) = -6
(8(-2) - 3) -(7(-2)+1) = -6
(-16 - 3) -(-14 + 1) = -6
(-19)+ (14 - 1) = -6
-19 + 13 = -6
-6 = -6

Answer 3

Reworking the problem as we speak, thanks for your help Hero your a big help.