Question

7 log base 9 (x+8)=7

Answer 1

divide by 7 to get
log9 (x+8) = 1
change to exponential form
9^1 = x+8
now solve for x....

Answer 2

When b raised to the power of y is equal x:
b y = x
Then base b logarithm of x is equal to y:
logb(x) = y
For example when:
24 = 16
Then
log2(16) = 4
Logarithm as inverse function of exponential function

The logarithmic function,
y = logb(x)
is the inverse function of the exponential function,
x = by
So if we calculate the exponential function of the logarithm of x (x>0),
f (f -1(x)) = blogb(x) = x
Or if we calculate the logarithm of the exponential function of x,
f -1(f (x)) = logb(bx) = x
Natural logarithm (ln)

Natural logarithm is a logarithm to the base e:
ln(x) = loge(x)
When e constant is the number:

Answer 3

how did you type all that that fast?

Answer 4

my typing is really very fast

Answer 5

i see....

Answer 6

thanks

Answer 7

yw

Answer 8

dpalnc is funny =))))