Question

-8 + log base 9 (m+1) =-8

Answer 1

Look over your laws of logs. . .they are imperative to know for this unit. . .

log(base 3) 45 - log(base 3) 9

= log_3 (45 / 9)
= log_3 (5)

and if solving. . .continue to. . .
= log5 / log3
= 1.4645

Remember. . .
log(base x)y + log(base x)z = log(base x)(y*z)
log(base x)y - log(base x)z = log(base x)(y/z)
log(base x)y = logy / logx
log(base x)y^x/t = x/t(log(base x)y)
The following site might be a great help to you. . .

http://oakroadsystems.com/math/loglaws.h …


log(base 2) 5 + log(base2) x - log(base 2) 10
= log(base 2)[(5x)/10]
= log(base 2)0.5x

log(base 2) 14 - log(base 2) 7
= log_2(14 / 7)
= log_2(2)

4log(base b) m + (1/2)log (base b) n - 3log(base b) p
= log_b(m)^4 + log_b(n)^(1/2) - log_b(p)^3
= log_b[(m^4*n^(1/2)) / (p^3)]
= log_b [(m^4*(sqrt)n) / (p^3)]