Please help with these 2 questions! Picture attached :)
17. If a secant segment and a tangent segment are drawn to a circle from an outside point, the length of the tangent segment is the geometric mean between the length of the entire secant segment and the portion of the secant segment lying in the exterior of the circle. AC is to AD as AD is to AB 12/AD = AD/ 3 (AD)^2 = 12*3 AD = 6
@Directrix , can u please draw it? i want to see. thanks
18. If sin theta = 0.56, theta is in quadrant 1 for theta in quadrant 1, |dw:1333264980197:dw| the remaining side can be found by Pyth. thm. =sqrt(1^2 - 0.56 ^2)=0.828 cos theta = 0.828 / 1 = 0.83
also, theta can be in quadrant 3. |dw:1333265221787:dw| this time, cos is -ve so, cos theta = -0.828 / 1 = -0.83
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