Question

Help with these 2 questions?

Answer 1

for the second question...

5² = 2x²
25 = 2x²
x² =25/2
x = sqrt(25/2) = 5/sqrt2 = 5sqrt2/2

Answer 2

For the second one, use pyth thm
\[a^2+b^2 = c^2\]
put a=x, b=x and c=5
you'll get
\[x^2+x^2 = 5^2\]
Can you solve it then?

Answer 3

For the first one,
area of sector = πr^2 x θ/360
Put r=4 and θ = 54 into the equation
area of sector = π [(4)^2] x 54/360
Again, can you solve it ?