Test
\[\int\limits \frac{\int \frac{\int \frac{\int \frac{\int \frac{\int \frac{1}{(p x+q)^n \sqrt{a x+b}} \, dx=-\frac{(p x+q)^{1-n} \sqrt{\frac{p (a x+b)}{b p-a q}} \, _2F_1\left(\frac{1}{2},1-n;2-n;\frac{a (q+p x)}{a q-b p}\right)}{(n-1) p \sqrt{a x+b}}+c}{(p x+q)^n \sqrt{a x+b}} \, dx=-\frac{(p x+q)^{1-n} \sqrt{\frac{p (a x+b)}{b p-a q}} \, _2F_1\left(\frac{1}{2},1-n;2-n;\frac{a (q+p x)}{a q-b p}\right)}{(n-1) p \sqrt{a x+b}}+c}{(p x+q)^n \sqrt{a x+b}} \, dx=-\frac{(p x+q)^{1-n} \sqrt{\frac{p (a x+b)}{b p-a q}} \, _2F_1\left(\frac{1}{2},1-n;2-n;\frac{a (q+p x)}{a q-b p}\right)}{(n-1) p \sqrt{a x+b}}+c}{(p x+q)^n \sqrt{a x+b}} \, dx=-\frac{(p x+q)^{1-n} \sqrt{\frac{p (a x+b)}{b p-a q}} \, _2F_1\left(\frac{1}{2},1-n;2-n;\frac{a (q+p x)}{a q-b p}\right)}{(n-1) p \sqrt{a x+b}}+c}{(p x+q)^n \sqrt{a x+b}} \, dx=-\frac{(p x+q)^{1-n} \sqrt{\frac{p (a x+b)}{b p-a q}} \, _2F_1\left(\frac{1}{2},1-n;2-n;\frac{a (q+p x)}{a q-b p}\right)}{(n-1) p \sqrt{a x+b}}+c}{(p x+q)^n \sqrt{a x+b}} \, dx=-\frac{(p x+q)^{1-n} \sqrt{\frac{p (a x+b)}{b p-a q}} \, _2F_1\left(\frac{1}{2},1-n;2-n;\frac{a (q+p x)}{a q-b p}\right)}{(n-1) p \sqrt{a x+b}}+c\]
\[\!\(\*TagBox[TagBox[RowBox[{"Integral]", RowBox[{FractionBox["1", RowBox[{SuperscriptBox[RowBox[{"(", RowBox[{RowBox[{"p", " ", "x"}], "+", "q"}], ")"}], "n"], " ", SqrtBox[RowBox[{RowBox[{"a", " ", "x"}], "+", "b"}]]}]], RowBox[{"\[DifferentialD]", "x"}]}]}],HoldForm],PolynomialForm[#, TraditionalOrder -> False]& ]\) == -(((p x + q)^( 1 - n) Sqrt[(p (a x + b))/(b p - a q)] Hypergeometric2F1[ 1/2,1 - n,2 - n,(a (q + p x))/(a q - b p)])/((n - 1) p Sqrt[ a x + b])) + c\]
\[\huge \frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{1}{2}}{3}}{4}}{5}}{6}}{7}}{8}}{9}}{\frac{9}{\frac{8}{\frac{7}{\frac{6}{\frac{5}{\frac{4}{\frac{3}{\frac{2}{\frac{1}{{}}}}}}}}}}}\]
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