A cargo plane left an airport at noon and flew toward New York at the average rate of 300 mph. at 2pm a jet plane left the same airport for New York and flew the same route as the cargo plane at the average rate of 500mph. how many miles did the jet plane fly before it overtook the cargo plane?

Question

anonymous · Answer

$$600+300t=500t$$ solve for t to get the time they met

anonymous · Answer

reasoning is that in two hours the first plane went 600 miles, and then its distance is $600+300t$ and the other planes distance is $500t$ 
since they meet at the same distance can set $600+300t=500t$ and solve for t to get $t=3$

anonymous · Answer

in 3 hours both planes have gone 1500 miles

hoblos · Answer

let t= time that the jet plane fly before it overtook the cargo plane
500t = 300(t+2)
500t = 300t +600
200t= 600
  t=3 hr

distance = speed x time = 500 x 3 =1500 mile

anonymous · Answer

thanks..!!