Can anyone give a hand with H3P4: DIODE LIMITER, trying to find the current through Diode 1 and 2 in this circuit - https://6002x.mitx.mit.edu/static/circuits/diode-limiter.gif

where R = 5.6k
V1 = 3.25v
V2 = 3v

Peak voltage of AC source is 7.5V

Any help on how to do the thevenin method would be great

Question

Can anyone give a hand with H3P4: DIODE LIMITER, trying to find the current through Diode 1 and 2 in this circuit - https://6002x.mitx.mit.edu/static/circuits/diode-limiter.gif

where R = 5.6k
V1 = 3.25v
V2 = 3v

Peak voltage of AC source is 7.5V 

Any help on how to do the thevenin method would be great

anonymous · Answer

For Diode 2= (-V2/R)-((V2+Vin)/R)

For D1 same prices, just remember who is working and who is not, also, use same procces for calculating the equation for D1,( lck )

anonymous · Answer

how can i find here the maximun currente

anonymous · Answer

D1: (Vs-V1)/R - V1/R D2: (-Vs+V2)/R - (-V2)/R 
D2: (-Vs+V2)/R - (-V2)/R 
where Vs=7.5V V1 =3.25V, V2 = 3V and R=5600ohm