Question

Solve x2 + 10x + 24 = 0 by completing the square. Show your work for full credit.

Answer 1

\[(x^2+10x+24=0\]
\[x^2+10x=-24\]
\[(x+5)^2=-24+25=1\]
\[x+5=\pm1\]
\[x=1-5, x=-1-5\]
\[x=-4,x=-6\]

Answer 2

x2 + 10x + 24 = 0

(x2 + 10x) + 24 = 0

(x) (x + 10) + 24 = 0

(x+5) (x+5) + 24-5^2 = 0

etc