Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

A. y = x - 3
B. y = x + 17
C. y = -3x - 3
D. y = -3x + 17

Answer 1

the line in point slope form is y = -3x + 7

The gradient(slope) of the line is -3

A perpendicular has a gradient of -1/m

Using the data the slope of the perpendicular is -1/(-3) = 1/3

in point slops form the line is

y = 1/3 x + b

Use the point (6, - 1) to find b

-1 = 1/3 (6) + b

b = -3

the line is

y = 1/3 x - 3

perhaps there is a typo in you choices...